PHP:Panoya kopyala
$result = mysqli_query($con,"SELECT * FROM keken WHERE kek LIKE ".$q); while($row = mysqli_fetch_array($result)) $result = mysqli_query($con,"SELECT * FROM welemen WHERE welem LIKE ".$q); while($row = mysqli_fetch_array($result)) echo ""; mysqli_close($con);


Yukarıdaki kodda
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool given in /srv/disk1/hosting_idsi/www/hequndae.tk/database/index.php on line 90
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool given in /srv/disk1/hosting_idsi/www/hequndae.tk/database/index.php on line 100
Hatası alıyorum. Neden olabilir?